Question 6

First, identify the compounds from the given reaction sequences:

1. $Xe + 2F_2 (1:5 \text{ ratio}) \rightarrow XeF_4$. Thus, $P$ is $XeF_4$.
2. $XeF_4 + O_2F_2 \rightarrow XeF_6 + O_2$. Thus, $Q$ is $XeF_6$.
3. Complete hydrolysis of $XeF_6$: $XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF$. Thus, $R$ is $XeO_3$.

Now evaluate the options: (A) $XeF_4$ has 8 valence electrons from $Xe$. It forms 4 sigma bonds with $F$ and has 2 lone pairs ($sp^3d^2$ hybridization, square planar shape). Statement is correct. (B) $XeF_6$ has 6 bond pairs and 1 lone pair on $Xe$. Its geometry is distorted octahedral, not perfect octahedral. Statement is incorrect. (C) $XeF_6$ is a very strong fluorinating agent (e.g., it can fluorinate silica). Statement is correct. (D) $XeO_3$ has $Xe$ forming 3 double bonds with Oxygen and possesses 1 lone pair ($sp^3$ hybridization). Its molecular structure is trigonal pyramidal. Statement is correct.