Question 4

SCQHARD

A known artificial sweetener XX is composed of 4-chloro-4-deoxy-α\alpha-D-galactose and 1,6-dichloro-1,6-dideoxy-β\beta-D-fructose joined by a glycosidic linkage. Structure of D-galactose is given below:

CHO∣H−C−OH∣HO−C−H∣HO−C−H∣H−C−OH∣CH2OH=D-galactose\begin{array}{c} \text{CHO} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{HO}-\text{C}-\text{H} \\ | \\ \text{H}-\text{C}-\text{OH} \\ | \\ \text{CH}_2\text{OH} \end{array} = \text{D-galactose}

The correct structure of XX is

(A)
Option A
(B)
Option B
(C)
Option C
(D)
Option D

Detailed Solution

The artificial sweetener X described is Sucralose.

  1. Monosaccharide Units: It consists of a 4-chloro-4-deoxy-α\alpha-D-galactopyranose unit and a 1,6-dichloro-1,6-dideoxy-β\beta-D-fructofuranose unit.

  2. Stereochemistry at C4 of Galactose: In D-galactose (as seen in the given Fischer projection, the -OH group at C4 is on the left), which corresponds to the 'up' (axial) position in the 3D chair/Haworth projection. Therefore, for the 4-chloro-4-deoxy-α\alpha-D-galactose unit, the Chlorine atom at C4 must also be in the 'up' (axial) position.

  3. Analyzing the Options (Left Ring):

    • In Option (A), the Cl atom at C4 of the left pyranose ring is pointing up (axial). This correctly represents the galacto configuration.

    • In Option (B), the Cl atom at C4 is pointing down (equatorial). This represents a gluco configuration, which contradicts the given IUPAC name.

  4. Glycosidic Linkage & Fructose Unit: The units are joined by an α(1→2)\alpha(1 \to 2) glycosidic bond (linkage between C1 of the galactose pyranose ring and C2 of the fructose furanose ring). The fructose unit has chlorine atoms at C1 and C6 (forming −CH2Cl-CH_2Cl groups). Option (A) correctly depicts both the α(1→2)\alpha(1 \to 2) linkage and the chlorinated fructose unit.

Thus, Option (A) is the correct structure.

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