Question 17

NUMERICALHARD

Synthesis and Quantitative Nitrogen and Sulphur Analysis

Consider the following reaction sequence in which J,K,LJ, K, L and MM are the major products.

Passage

The volume of 11 M aqueous H2SO4H_2SO_4 required to completely neutralize the ammonia evolved from 5.725.72 g of LL in Kjeldahl's method of nitrogen estimation is ____ mL.

Correct Answer: 10

Detailed Solution

  1. Identify product L: Starting from mm-xylene (C8H10C_8H_{10}), Friedel-Crafts acylation followed by Finkelstein and SN2S_N2 substitution with sodium 3-nitrophenolate yields JJ (C16H15NO4C_{16}H_{15}NO_4).

Reduction of the ketone to an alcohol followed by bromination gives KK (C16H16BrNO3C_{16}H_{16}BrNO_3) with a molar mass of 350350 g/mol. KK reacts with excess NH3NH_3 to replace −Br-Br with −NH2-NH_2, forming LL (C16H18N2O3C_{16}H_{18}N_2O_3).

The molar mass of LL is 192(C)+18(H)+28(N)+48(O)=286192(C) + 18(H) + 28(N) + 48(O) = 286 g/mol.

  1. Kjeldahl's Method: In this method, only the nitrogen from the amine group (−NH2-NH_2) is converted to NH3NH_3. Nitrogen in the nitro group (−NO2-NO_2) is not estimated by this method.

  2. Calculation: Moles of L=5.72286=0.02L = \frac{5.72}{286} = 0.02 mol. Since each molecule of LL provides 11 estimated nitrogen atom, moles of NH3NH_3 evolved = 0.020.02 mol.

The neutralization reaction is: 2NH3+H2SO4→(NH4)2SO42NH_3 + H_2SO_4 \rightarrow (NH_4)_2SO_4.

Moles of H2SO4H_2SO_4 required = 0.022=0.01\frac{0.02}{2} = 0.01 mol.

Volume of 11 M H2SO4=0.01 mol1 mol/L=0.01H_2SO_4 = \frac{0.01 \text{ mol}}{1 \text{ mol/L}} = 0.01 L = 1010 mL.

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