Question 13

MATRIX MATCHMEDIUM

List-I contains various physical/chemical processes, and List-II contains combinations of changes in enthalpy (ΔH\Delta H) and entropy (ΔS\Delta S). Match each entry in List-I to the appropriate entry in List-II, and choose the correct option.

List - I

P

Physisorption

Q

Diamond →\to Graphite

R

Denaturation of protein

S

Propene →\to Cyclopropane

List-II

1

ΔH>0\Delta H > 0 and ΔS>0\Delta S > 0

2

ΔH<0\Delta H < 0 and ΔS<0\Delta S < 0

3

ΔH<0\Delta H < 0 and ΔS=0\Delta S = 0

4

ΔH>0\Delta H > 0 and ΔS<0\Delta S < 0

5

ΔH<0\Delta H < 0 and ΔS>0\Delta S > 0

(A)

P-2, Q-3, R-5, S-4

(B)

P-4, Q-3, R-5, S-1

(C)

P-2, Q-5, R-1, S-4

(D)

P-2, Q-5, R-1, S-3

Detailed Solution

(P) Physisorption is an exothermic process (ΔH<0\Delta H < 0) and results in a decrease in entropy (ΔS<0\Delta S < 0) because the gas molecules are restricted to the surface. Matches (2).

(Q) Graphite is the more stable allotrope of carbon at standard conditions. The conversion of Diamond →\to Graphite is exothermic (ΔH<0\Delta H < 0) and the entropy increases (ΔS>0\Delta S > 0) because graphite has a more disordered layered structure compared to the rigid diamond lattice. Matches (5).

(R) Denaturation of protein involves the unfolding of the highly ordered native structure into a random coil, leading to an increase in entropy (ΔS>0\Delta S > 0). This process typically requires energy to break hydrogen bonds, making it endothermic (ΔH>0\Delta H > 0). Matches (1).

(S) The conversion of Propene (an open-chain alkene) to Cyclopropane (a strained ring) is endothermic (ΔH>0\Delta H > 0) due to the high ring strain in cyclopropane. Entropy decreases (ΔS<0\Delta S < 0) during ring formation as the degrees of freedom are reduced. Matches (4).

Correct matching: P-2, Q-5, R-1, S-4. Correct Option: C

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