Question 1

SCQMEDIUM

During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to

(A)

NOS−NOS^-

(B)

SCN−SCN^-

(C)

SNO−SNO^-

(D)

NCS−NCS^-

Detailed Solution

Sodium nitroprusside has the formula Na2[Fe(CN)5NO]Na_2[Fe(CN)_5NO].

In this complex, the nitrosyl ligand is present as NO+NO^+. When it reacts with the sulphide ion (S2−S^{2-}) in an aqueous solution, a purple-colored complex is formed:

[Fe(CN)5NO]2−+S2−→[Fe(CN)5NOS]4−[Fe(CN)_5NO]^{2-} + S^{2-} \rightarrow [Fe(CN)_5NOS]^{4-}

In this process, the NO+NO^+ ligand reacts with S2−S^{2-} to form the thionitrite ligand (NOS−NOS^-). Therefore, the ligand is converted to NOS−NOS^-.

Free Exam

Boost Your Exam Preparation!

Move beyond just reading solutions. Access our comprehensive Test Series, original Mock Tests, and interactive learning modules. Many premium tests are completely free!

  • Original Mocks & Regular Test Series
  • Real NTA-like Interface with Analytics
  • Many Free Tests Available