Question 6

1. iso-propylbenzene (Cumene) reacts with $O_2$ to form Cumene hydroperoxide, which on hydrolysis with $H_3O^+$ gives Phenol and Acetone ($P$).

So, $P$ is $CH_3COCH_3$.

2. $P$ ($CH_3COCH_3$) with 3 equivalents of $Cl_2$ undergo alpha-halogenation to give 1,1,1-trichloroacetone ($Q$), which is $Cl_3CCOCH_3$.

3. $Q$ ($Cl_3CCOCH_3$) treated with $Ca(OH)_2$ undergoes the haloform reaction to produce Chloroform ($R$, $CHCl_3$) and Calcium acetate ($S$, $(CH_3COO)_2Ca$).

Analyzing options:

(A) Acetone ($P$) reacts with Chloroform ($R$) in the presence of $KOH$ to form Chloretone ($(CH_3)_2C(OH)CCl_3$). Correct.

(B) Chloroform ($R$, $CHCl_3$) reacts with $O_2$ in the presence of light to form Carbonyl chloride ($COCl_2$), also known as phosgene. Correct.

(C) $Q$ ($Cl_3CCOCH_3$) with aq. $NaOH$ undergoes haloform cleavage to give $CHCl_3$ and $CH_3COONa$, not the disproportionation products of chloral. Incorrect.

(D) Calcium acetate ($S$) on dry distillation (heating) produces acetone ($P$) and $CaCO_3$. Correct.