Question 705071

SCQMEDIUM

Helium atom is excited to a state with the configuration $(2s2p)$ with an energy $58.3$ eV. After some time, this atom spontaneously ejects a single electron. The value of the orbital angular momentum quantum number $(l)$ of the ejected electron in the final state of the system is (ionization potential of $He(1s)^2$ is $24.6$ eV)

(A)

(B)

(C)

(D)

Detailed Solution

The configuration of the excited state is $2s2p$ . When an electron is ejected from the excited state, it is most likely to come from the $p$ -orbital rather than the $s$ -orbital. Thus, the orbital angular momentum of the ejected electron is $l = 1$ .

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