Question 705017

For a 250 m stretch, the broken lines consist of segments of 2.5 m followed by 2.5 m gaps. Each cycle is 5 m long. In 250 m, there are $250 / 5 = 50$ cycles. Each cycle has 2.5 m of paint. There are 2 such lines between 3 lanes, so $2 \times (50 \times 2.5) = 250$ m. Additionally, there are 2 continuous boundary lines of 250 m each, so $2 \times 250 = 500$ m. Total length $= 250 + 500 = 750$ m.