Question 705013

SCQMEDIUM

If 32XY632XY6 is divisible by 9, XX and YY being even decimal digits, then XX =

(A)

2

(B)

4

(C)

6

(D)

8

Detailed Solution

For a number to be divisible by 9, the sum of its digits must be divisible by 9. Sum = 3+2+X+Y+6=11+X+Y3 + 2 + X + Y + 6 = 11 + X + Y. Given X,YX, Y are even digits (0,2,4,6,8)(0, 2, 4, 6, 8). If X=8X=8 and Y=8Y=8, sum = 11+16=2711 + 16 = 27, which is divisible by 9.

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