Question 705007

SCQMEDIUM

Areas and populations of four states S1, S2, S3 and S4 are shown. Their arrangement in decreasing order of population density would be:

(A)

S4, S3, S1, S2

(B)

S1, S2, S3, S4

(C)

S4, S1, S3, S2

(D)

S2, S1, S3, S4

Detailed Solution

Population density is defined as $\text{Population} / \text{Area}$ . Using the data:

Density(S1) = $110/300 \approx 0.367$ , Density(S2) = $25/130 \approx 0.227$ , Density(S3) = $70/120 \approx 0.63$ , Density(S4) = $90/90 = 1$ .

The order is $S4 (1) > S3 (0.63) > S1 (0.367) > S2 (0.227)$ .

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