Question 2

Hydrolysis of interhalogen compounds of the type $XY_n$ (where $X$ is the larger, more electropositive halogen) produces the oxyacid of $X$ and the halide acid of $Y$. The oxidation state of $X$ remains unchanged during hydrolysis.

1. For $ICl$ ($I$ is in $+1$ state): $ICl + H_2O ightarrow HOI + HCl$. The oxyanion produced is $IO^-$.
2. For $ClF_3$ ($Cl$ is in $+3$ state): $ClF_3 + 2H_2O ightarrow HClO_2 + 3HF$. The oxyanion produced is $ClO_2^-$.
3. For $BrF_5$ ($Br$ is in $+5$ state): $BrF_5 + 3H_2O ightarrow HBrO_3 + 5HF$. The oxyanion produced is $BrO_3^-$. Thus, the ions produced are $IO^-$, $ClO_2^-$, and $BrO_3^-$, respectively.