Question 2

SCQMEDIUM

The correct order of the wavelength maxima of the absorption band in the ultraviolet-visible region for the given complexes is

(A)

[Co(CN)6]3−<[Co(NH3)6]3+<[Co(NH3)5(H2O)]3+<[Co(NH3)5(Cl)]2+[Co(CN)_6]^{3-} < [Co(NH_3)_6]^{3+} < [Co(NH_3)_5(H_2O)]^{3+} < [Co(NH_3)_5(Cl)]^{2+}

(B)

[Co(NH3)5(Cl)]2+<[Co(NH3)5(H2O)]3+<[Co(NH3)6]3+<[Co(CN)6]3−[Co(NH_3)_5(Cl)]^{2+} < [Co(NH_3)_5(H_2O)]^{3+} < [Co(NH_3)_6]^{3+} < [Co(CN)_6]^{3-}

(C)

[Co(CN)6]3−<[Co(NH3)5(Cl)]2+<[Co(NH3)5(H2O)]3+<[Co(NH3)6]3+[Co(CN)_6]^{3-} < [Co(NH_3)_5(Cl)]^{2+} < [Co(NH_3)_5(H_2O)]^{3+} < [Co(NH_3)_6]^{3+}

(D)

[Co(NH3)6]3+<[Co(CN)6]3−<[Co(NH3)5(Cl)]2+<[Co(NH3)5(H2O)]3+[Co(NH_3)_6]^{3+} < [Co(CN)_6]^{3-} < [Co(NH_3)_5(Cl)]^{2+} < [Co(NH_3)_5(H_2O)]^{3+}

Detailed Solution

The energy of the absorption band (ΔoΔ_o) depends on the strength of the ligands in the spectrochemical series. According to the spectrochemical series, the strength of the ligands is: Cl−<H2O<NH3<CN−Cl^- < H_2O < NH_3 < CN^-. The crystal field splitting energy (ΔoΔ_o) follows the same order as ligand strength. Since energy (EE) is inversely proportional to wavelength (λλ), E=hcλE = \frac{hc}{λ}, the order of wavelength maxima (λmaxλ_{max}) will be the inverse of the ligand strength order: CN−<NH3<H2O<Cl−CN^- < NH_3 < H_2O < Cl^-. Therefore, the order of wavelength maxima is: [Co(CN)6]3−<[Co(NH3)6]3+<[Co(NH3)5(H2O)]3+<[Co(NH3)5(Cl)]2+[Co(CN)_6]^{3-} < [Co(NH_3)_6]^{3+} < [Co(NH_3)_5(H_2O)]^{3+} < [Co(NH_3)_5(Cl)]^{2+}.

Free Exam

Boost Your Exam Preparation!

Move beyond just reading solutions. Access our comprehensive Test Series, original Mock Tests, and interactive learning modules. Many premium tests are completely free!

  • Original Mocks & Regular Test Series
  • Real NTA-like Interface with Analytics
  • Many Free Tests Available