Question 16

MATRIX MATCHHARD

Match the compounds in List-I with the appropriate observations in List-II and choose the correct option.

List - I

List-II

Reaction with phenyl diazonium salt gives yellow dye.

Reaction with ninhydrin gives purple color and it also reacts with $\text{FeCl}_3$ to give violet color.

Reaction with glucose will give corresponding hydrazone.

Lassaigne extract of the compound treated with dilute $\text{HCl}$ followed by addition of aqueous $\text{FeCl}_3$ gives blood red color.

After complete hydrolysis, it will give ninhydrin test and it DOES NOT give positive phthalein dye test.

Correct Match:

P → 2

Q → 5

R → 1

S → 3

Detailed Solution

P matches with (2): The compound contains a free $-\text{NH}_2$ group (alpha to carbonyl) which gives a purple color with ninhydrin, and a phenolic $-\text{OH}$ group which gives a violet color with neutral $\text{FeCl}_3$ .

Q matches with (5): Complete hydrolysis of the acetylated peptide releases free amino acids that give a positive ninhydrin test. However, it lacks a phenolic group, so it does not give a positive phthalein dye test.

R matches with (1): Anilinium chloride ( $C_6H_5\text{NH}_3^+\text{Cl}^-$ ) in equilibrium with aniline reacts with phenyl diazonium salts to undergo coupling reactions, typically forming yellow/orange dyes (e.g., p-aminoazobenzene).

S matches with (3): The compound is a substituted hydrazine (2,4,6-trimethylphenylhydrazine). Hydrazines react with the carbonyl group of glucose to form hydrazones (and subsequently osazones).

Correct Option: B

Question 16

List - I

List-II

Correct Match:

Detailed Solution

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