Question 705045

The circuit consists of an op-amp differentiator followed by an RC integrator.

The first stage acts as a differentiator, producing spikes at the transitions of the square wave input. Since the input is a square wave with period $T \ll RC$, the differentiating action produces sharp pulses. The subsequent RC circuit acts as an integrator.

Integrating the spikes (which are essentially impulse functions $\delta(t)$) restores the signal to a square wave shape.

Thus, the overall transfer function results in the output being a square wave.